Water is moving with a speed of $5.18 ms^{-1}$ through a pipe with a cross-sectional area of $4.20 cm^2$. The water gradually descends $ 9.66 m $ as the pipe increase in area to $7.60 cm^2$. The speed of flow at the lower level is ....... $ms^{-1}$
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(d)${a_1}{v_1} = {a_2}{v_2}$
==> $4.20 \times 5.18 = 7.60 \times {v_2} \Rightarrow {v_2} = 2.86\;m/s$
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