Applying Bernoullis equation
$P_1+\rho g h+\frac{1}{2} \rho v_1^2=P_2+\rho g h+\frac{1}{2} \rho v_2^2$
$\frac{1}{2} \times \rho\left[v_1^2-v_2^2\right]=P_2-P_1=\Delta P$
$\Rightarrow \frac{1}{2} \times 1.293\left[(60)^2-(45)^2\right]=\Delta P$
$\Rightarrow 1018 \,N / m ^2 \simeq \Delta P$


| Column - $\mathrm{I}$ | Column - $\mathrm{II}$ |
| $(a)$ Velocity head | $(i)$ $\frac{P}{{\rho g}}$ |
| $(b)$ Pressure head | $(ii)$ $h$ |
| $(iii)$ $\frac{{{v^2}}}{{2g}}$ |