Air streams horizontally past an air plane. The speed over the top surface is $60 \,m / s$ and that under the bottom surface is $45 \,m / s$. The density of air is $1.293 \,kg / m ^3$, then the difference in pressure is ....... $N / m ^2$
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(a)

Applying Bernoullis equation

$P_1+\rho g h+\frac{1}{2} \rho v_1^2=P_2+\rho g h+\frac{1}{2} \rho v_2^2$

$\frac{1}{2} \times \rho\left[v_1^2-v_2^2\right]=P_2-P_1=\Delta P$

$\Rightarrow \frac{1}{2} \times 1.293\left[(60)^2-(45)^2\right]=\Delta P$

$\Rightarrow 1018 \,N / m ^2 \simeq \Delta P$

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