Question
What are the oxidation number of the underlined elements in the following and how do you rationalise your results?
$\mathrm{CH}_3 \mathrm{COOH}$
$\mathrm{CH}_3 \mathrm{COOH}$
✓
Answer
$2(x)+4(+1)+2(-2)=0$ or, $2 x=0$ or, $x=0$ However, 0 is average $O . N$. of $C$. The two carbon atoms present in this molecule are present in different environments. Hence, they cannot have the same oxidation number. Thus, C exhibits the oxidation states of +2 and -2 in $\mathrm{CH}_3 \mathrm{COOH}$.
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