Question
What are the oxidation number of the underlined elements in the following and how do you rationalise your results?
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}$

Answer

2 (x) + 6 (+1) + 1 (-2) = 0
or, 2x + 4 = 0
or, x = -2
Hence, the O.N. of C is -2.

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