Question
What happens when.
$\mathrm{BF}_3$ is reacted with ammonia?

Answer

$\mathrm{BF}_3$ (a Lewis acid) reacts with $\mathrm{NH}_3$ (a Lewis base) to form an adduct. This results in a complete octet around B in $\mathrm{BF}_3$.
$\text{F}_3\text{B}+:\text{NH}_3\rightarrow \text{F}_3\text{B}\leftarrow:\text{NH}_3$

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