Question
Balance $\text{P}+\text{HNO}_3\xrightarrow{ \ \ \ \ \ \ \ \ }\text{H}_3\text{PO}_4+\text{NO}_2+\text{H}_2\text{O}$ by oxidation number method.

Answer



Multiply P by l, $\text{HNO}_3$ by 5, we get$\text{P}+5\text{HNO}_3\xrightarrow{ \ \ \ \ \ \ \ \ }\text{H}_3\text{PO}_4+5\text{NO}_2+\text{H}_2\text{O}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free