MCQ
What is the dimensional formula of $a b^{-1}$ in the equation $\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}$, where letters have their usual meaning.
  • A
    $\left[\mathrm{M}^6 \mathrm{~L}^3 \mathrm{~T}^{-2}\right]$
  • $\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]$
  • C
    $\left[M^{-1} L^j T^3\right]$
  • D
    $\left[M^6 L^7 T^4\right]$

Answer

Correct option: B.
$\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]$
b
$\because[\mathrm{V}]=[\mathrm{b}]$

$\therefore \text { Dimension of } \mathrm{b}=\left[\mathrm{L}^3\right]$

$\&[\mathrm{P}]=\left[\frac{\mathrm{a}}{\mathrm{V}^2}\right]$

${[\mathrm{a}]=\left[\mathrm{PV}^2\right]=\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]\left[\mathrm{L}^6\right]}$

$\text { Dimension of } \mathrm{a}=\left[\mathrm{ML}^5 \mathrm{~T}^{-2}\right]$

$\therefore \mathrm{ab}^{-1}=\frac{\left[\mathrm{ML}^5 \mathrm{~T}^{-2}\right]}{\left[\mathrm{L}^3\right]}=\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]$

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