Chemical Bonding and Molecular Structure — Chemistry STD 11 Science — Question

$N_2$

14

$\text{KK}\ \sigma2\text{s}^{2}\sigma^{*}2\text{s}^{2}\ \pi2\text{p}^{2}_\text{x}=\pi2\text{p}^{2}_{\text{y}}$

$\frac{8-2}{2}=3$

$N^+_2$

13

$\text{KK}\ \sigma2\text{s}^{2}\sigma^{*}2\text{s}^{2}\ \pi2\text{p}^{2}_\text{x}=\pi2\text{p}^{2}_{\text{y}}\ \sigma2\text{p}_\text{z}$

$\frac{7-2}{2}=2.5$

Bond order decreases from 3 to 2.5

$O_2$

16

$\text{KK}\ \sigma2\text{s}^{2}\sigma^{*}2\text{s}^{2}\ \pi2\text{p}^{2}_\text{x}\ \pi^{*}2\text{p}^{2}_\text{x}=\pi2\text{p}^{2}_{\text{y}}\ \sigma2\text{p}_\text{z}$

$\frac{8-4}{2}=2.0$

$O^+_2$

15

$\text{KK}\ \sigma2\text{s}^{2}\sigma^{*}2\text{s}^{2}\ \pi2\text{p}^{2}_\text{x}=\pi2\text{p}^{2}_{\text{y}}\ \sigma2\text{p}_\text{z}\ \pi^{*}2\text{p}^{2}_{\text{y}}$

$\frac{8-3}{2}=2.5$

Bond order decreases from 2 to 2.5