What is the equilibrium expression for the reaction P_ 4(s) + 5 O… - Vidyadip

MCQ

What is the equilibrium expression for the reaction ${P_{4(s)}} + 5{O_{2(g)}}$ $\rightleftharpoons$ ${P_4}{O_{10(s)}}$

A
${K_c} = {[{O_2}]^5}$
B
${K_c} = [{P_4}{O_{10}}]/5[{P_4}][{O_2}]$
C
${K_c} = [{P_4}{O_{10}}]/[{P_4}]{[{O_2}]^5}$
✓
${K_c} = 1/{[{O_2}]^5}$

✓

Answer

Correct option: D.

${K_c} = 1/{[{O_2}]^5}$

(d) ${P_4}_{(s)} + 5{O_2}_{(g)}$ $\rightleftharpoons$ ${P_4}{O_{10}}_{(s)}$

${K_c} = \frac{{[{P_4}{O_{10}}(s)]}}{{[{P_4}(s)]{{[{O_2}(g)]}^5}}}$

We know that concentration of a solid component is always taken as unity

${K_c} = \frac{1}{{{{[{O_2}]}^5}}}$

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