What is the magnitude of magnetic force per unit length (in $N \;m ^{-1}$) on a wire carrying a current of $8\; A$ and making an angle of $30^o$ with the direction of a uniform magnetic field of $0.15\;T$?
Easy
Download our app for free and get started
Current in the wire, $I=8 \,A$
Magnitude of the uniform magnetic field, $B =0.15 \,T$
Angle between the wire and magnetic field, $\theta=30^{\circ}$
Magnetic force per unit length on the wire is given as
$f=B I \sin \theta$
$=0.15 \times 8 \times 1 \times \sin 30^{\circ}$
$=0.6\, N\, m ^{-1}$
Hence, the magnetic force per unit length on the wire is $0.6 \;N \,m ^{-1}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionEnergy in a current carrying coil is stored in the form of
- 2A galvanometer has a resistance of $20\,\Omega$ and reads full-scale when $0.2\, V$ is applied across it. To convert it into a $10\, A$ ammeter, the galvanometer coil should have aView Solution
- 3An electron (mass $= 9 \times 10^{-31}\,kg$. Charge $= 1.6 \times 10^{-19}\,C$) whose kinetic energy is $7.2 \times 10^{-18}$ $joule$ is moving in a circular orbit in a magnetic field of $9 \times 10^{-5} \,weber/m^2$. The radius of the orbit is.....$cm$View Solution
- 4The oscillator frequency of a cyclotron is $10 \,MHz$. What should be the operating magnetic field for accelerating proton is ......... $T$View Solution
- 5Net magnetic field at the centre of the circle $O$ due to a current carrying loop as shown in figure is $(\theta < 180^o)$View Solution
- 6View SolutionWhen the current flowing in a circular coil is doubled and the number of turns of the coil in it is halved, the magnetic field at its centre will become
- 7View SolutionBy ammeter, which of the following can be measured
- 8View SolutionTesla is a unit for measuring
- 9A small circular loop of conducting wire has radius $a$ and carries current $I$. It is placed in a uniform magnetic field $\mathrm{B}$ perpendicular to its plane such that when rotated slightly about its diameter and released, it starts performing simple harmonic motion of time period $T$. If the mass of the loop is $m$ thenView Solution
- 10The magnetic field existing in a region is given by $\vec B\, = {B_0}\,\left[ {1 + \frac{x}{l}} \right]\,\hat k\,A$ square loop of edge $l$ and carrying current $I_0$ , is placed with its edges parallel to the $x-y$ axis . Find the magnitude of the net magnetic force experienced by the loopView Solution