Question
What is the ratio of the distances covered by a freely falling object in its first and second seconds?

Answer

 $\begin{array}{l}s_1=0+\frac{1}{2} g(2 \times 1-1)=\frac{1}{2} g \\ s_2=0+\frac{1}{2} g(2 \times 2-1)=\frac{3}{2} g\end{array}$
$\therefore \quad s_1: s_2=1: 3$

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