Question
What volume of 0.1 M NaOH solution is required to neutralise 100 ml of concentrated aqueous sulphuric acid which contains $98 \% \mathrm{~H}_2 \mathrm{SO}_4$ by mass. The density of concentrated sulphuric acid solution is $1.84 \mathrm{g} \mathrm{ml}^{-1} \mathrm{NaOH}$ reacts with $\mathrm{H}_2 \mathrm{SO}_4$ according to the following reaction:
$2 \mathrm{NaOH}+\mathrm{H}_2 \mathrm{SO} 4 \rightarrow \mathrm{Na}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}$
(Atomic mass $/ \mathrm{g} \mathrm{mol}^{-1} \mathrm{H}=1, \mathrm{~S}=32, \mathrm{O}=16$ ).
$2 \mathrm{NaOH}+\mathrm{H}_2 \mathrm{SO} 4 \rightarrow \mathrm{Na}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}$
(Atomic mass $/ \mathrm{g} \mathrm{mol}^{-1} \mathrm{H}=1, \mathrm{~S}=32, \mathrm{O}=16$ ).