MCQ
What volume of oxygen gas $(O_2)$ measured at $0\,^o C$ and $1\ atm,$ is needed to burn completely $1\ L$ of propane gas $(C_3H_8)$ measured under the same conditions? .......... $\mathrm{L}$
- ✓$5$
- B$10$
- C$7$
- D$6$
✓
Answer
Correct option: A.
$5$
a
Volume of a gas at $STP =22.4 \mathrm{L}$
Volume of a gas at $STP =22.4 \mathrm{L}$
$\mathrm{C}_{3} \mathrm{H}_{8}+5 \mathrm{O}_{2} \rightarrow 3 \mathrm{CO}_{2}+4 \mathrm{H}_{2} \mathrm{O}$
$22.4 \mathrm{L} \quad 5 \times 22.4 \mathrm{L}$
Therefore, to burn $22.4 \mathrm{L} \;\mathrm{C}_{3} \mathrm{H}_{8}$ the oxygen required is $=5 \times 22.4 \mathrm{L}$
To burn $1 \mathrm{L\;C}_{3} \mathrm{H}_{8}$ the oxygen required will be $=5 \times 22.4 / 22.4=5 \mathrm{L}$
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