Question
When $2 \times 10^{10}$ electrons are transferred from one conductor to another, a potential difference of 20 V appears between the conductors. Find the capacitance of the two conductors.

Answer

Given: Number of electrons, $n=2 \times 10^{10}, V=20$ volt, $e=1.6 \times 10^{-19} C$
To find: $C=$ ?
Formula: $C=\frac{Q}{V}$
$\begin{array}{ll}\therefore & C=\frac{n e}{V}  \\ \therefore & C=\frac{2 \times 10^{10} \times 1.6 \times 10^{-19}}{20} \quad \quad (\because Q = ne) \\ \therefore & C=1.6 \times 10^{-10} F\end{array}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free