MCQ
When $23\, g$ $Na$ reacts with $1\, mole$ of propyne then how many mole of $H_2$ gas will be released......$mole$
  • A
    $1$
  • $0.5$
  • C
    $1.5$
  • D
    $2$

Answer

Correct option: B.
$0.5$
b
$C{{H}_{3}}-C\equiv CH+\underset{\begin{smallmatrix} 
 23\,gm \\ 
 \left( 1\,mole \right) 
\end{smallmatrix}}{\mathop{Na}}\,\longrightarrow C{{H}_{3}}\equiv {{C}^{\Theta }}N{{a}^{\oplus }}+\underset{\left( 1/2\,mole \right)}{\mathop{1/2{{H}_{2}}}}\,$

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