In the circuit diagram shown below, the magnitude and direction of the flow of current respectively would be
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Total resistance of the circuit

$R=1\, \Omega+2\, \Omega+3\, \Omega=6 \,\Omega$

Current, $\quad \mathrm{I}=\frac{10-4}{6}=1 \mathrm{\,amp}$

The direction of the current would be from $\mathrm{a}$ to $\mathrm{b}$ via $\mathrm{e}.$

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