MCQ
When $CrI_3$ oxidises to $Cr_2O_7^{-2}$ and $IO_4^-$ , equivalent mass of $CrI_3$ will be :-
- A$\frac{M}{33}$
- ✓$\frac{M}{27}$
- C$\frac{M}{28}$
- D$\frac{M}{24}$
$n-$factor $\Rightarrow \mathrm{Cr}=(+3\, \mathrm{to}\,+6)=3 \mathrm{e}^{-} \,lo \mathrm{ss}$
$I=(-1 \text { to }+7) \times 3=24 \mathrm{e}^{-} \,lo \mathrm{ss}$
$n-$factor $=27$
$\therefore E=\frac{M}{27}$
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