MCQ
When ethylene bromide is treated with $Zn,$ we get
- AAlkane
- ✓Alkene
- CAlkyne
- DAll
✓
Answer
Correct option: B.
Alkene
b
(b) $\begin{array}{*{20}{c}}
{C{H_2} - C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,} \\
{\,Br\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,}
\end{array} + Zn \to \mathop {C{H_2} = C{H_2}}\limits_{Alkene} + B{r_2}$
(b) $\begin{array}{*{20}{c}}
{C{H_2} - C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,} \\
{\,Br\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,}
\end{array} + Zn \to \mathop {C{H_2} = C{H_2}}\limits_{Alkene} + B{r_2}$
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