MCQ
When ${H_2}S$ is passed through acidified $KMn{O_4},$ we get
  • A
    ${K_2}S{O_3}$
  • B
    $Mn{O_2}$
  • C
    $KHS{O_3}$
  • $Sulphur$

Answer

Correct option: D.
$Sulphur$
d
(d) $2KMn{O_4} + 3{H_2}S{O_4} + 5{H_2}S\, \to \,$

${K_2}S{O_4} + 2MnS{O_4} + 8{H_2}O + 5S$

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