MCQ
When iodine reacts with sodium thiosulphate, the oxidation state of sulphur changes from +4 to __________ .
- A-2
- B+2
- C$+\frac{3}{2}$
- D$+\frac{5}{2}$
✓
Answer
D. $+\frac{5}{2}$
Explanation:
$I_2+2 \stackrel{+4}{S_2} O_{3(a q)}^{2-} \rightarrow \stackrel{+\frac{5}{S^2}}{S_4} O_{6(a q)}^{2-}+2 I_{(a q)}^{-}$
S has fractional oxidation state in the product.
Explanation:
$I_2+2 \stackrel{+4}{S_2} O_{3(a q)}^{2-} \rightarrow \stackrel{+\frac{5}{S^2}}{S_4} O_{6(a q)}^{2-}+2 I_{(a q)}^{-}$
S has fractional oxidation state in the product.
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