MCQ
When the light source is kept $20 \mathrm{~cm}$ away from a photo cell, stopping potential $0.6 \mathrm{~V}$ is obtained. When source is kept $40 \mathrm{~cm}$ away, the stopping potential will be
- A$0.3 \mathrm{~V}$
- ✓$0.6 \mathrm{~V}$
- C$1.2 \mathrm{~V}$
- D$2.4 \mathrm{~V}$