When the temperature of a gas is $20^{\circ} C$ and pressure is changed from $P_1=1.01 \times 10^5 \,Pa$ to $P_2=1.165 \times$ $10^5 \,Pa$, then the volume changes by $10 \%$. The Bulk modulus is $........\times 10^5 \,Pa$
Medium
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$\frac{\Delta V}{V}=\frac{-\Delta P}{B}$ $\left\{\begin{array}{l}\Delta V=10 \% \text { of } V \text { ( } \because \text { Pressure increases volume must } \\ \text { If } \begin{array}{l}\text { decreases by } 10 \% \text { so we will use a +ve sign) }\end{array} \\ \begin{array}{rl}\Rightarrow \Delta V & =100 cc \\ \Delta P & =P_2-P_1 \\ & =1.165 \times 10^5-1.01 \times 10^5\end{array}\end{array}\right.$
Substituting the values
$\frac{-10}{100}=\frac{-\left(1.165 \times 10^6-1.01 \times 10^6\right)}{B}$
$\frac{1}{10}=\frac{.155 \times 10^5}{B}$
$B=1.55 \times 10^5 \,Pa$
Substituting the values
$\frac{-10}{100}=\frac{-\left(1.165 \times 10^6-1.01 \times 10^6\right)}{B}$
$\frac{1}{10}=\frac{.155 \times 10^5}{B}$
$B=1.55 \times 10^5 \,Pa$
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