When two identical capacitors are in series have $3\,\mu F$ capacitance and when parallel $12\,\mu F$. What is the capacitance of each.......$\mu \,F$
Medium
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(a) In series $C' = C/n$ i.e. $C = nC' = 2 \times 3 = 6\,\mu F$
In parallel $C' = nC$ i.e. $C = \frac{{C'}}{n} = \frac{{12}}{2} = 6\,\mu F$
In parallel $C' = nC$ i.e. $C = \frac{{C'}}{n} = \frac{{12}}{2} = 6\,\mu F$
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