Which compound in each of the following pairs will react faster in $\ce{S_N2}$ reaction with $–\ce{OH(CH_3)_3CCl}$ or $\ce{CH_3Cl}$.
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In $\ce{S_N2}$ mechanism nucleophile attack occur at the atom bearing the leaving group. In case of $\ce{CH_3Cl}$ there is no bulky substituents on the carbon atom or in case of $\ce{(CH_3)3CCl}$, the attack of the nucleophile at the carbon atom is hindered because of the presence of bulky group on the carbon atom. Hence $\ce{CH_3Cl}$ reacts faster than $\ce{(CH_3)_3CCl}$ in $\ce{S_N2}$ reaction with $\ce{OH_^}-$.
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