MCQ
Which doesn’t follow Markownikoff’s rule
- A$C{H_3} - CH = C{H_2}$
- ✓$C{H_3}CH = CHC{H_3}$
- C$C{H_3} - \mathop {\mathop {CH - }\limits_{|\,\,\,\,\,\,\,\,} }\limits_{C{H_3}\,\,} CH = C{H_2}$
- D$C{H_3} - C{H_2} - CH = C{H_2}$
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$(a)\; C \;\;(b)\; O \;\;(c)\; F\;\; (d) \;Cl\;\; (e)\; Br$
$2 \mathrm{Fe}_{(\mathrm{s})}+\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})}, \Delta \mathrm{H}^{\mathrm{o}}=-822 \mathrm{~kJ} / \mathrm{mol}$
$\mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{(\mathrm{g})}, \Delta \mathrm{H}^{\mathrm{o}}=-110 \mathrm{~kJ} / \mathrm{mol}$
Then enthalpy change for following reaction
$3\mathrm{C}_{(\mathrm{s})}+\mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})} \rightarrow 2 \mathrm{Fe}_{(\mathrm{s})}+3 \mathrm{CO}_{(\mathrm{g})}$