Which is formed when benzalamine react with nitrous acid
A${C_6}{H_5}OH$
B${C_6}{H_5}ON$
C${C_2}{H_5}{N_2}OH$
D${C_6}{H_5}C{H_2}OH$
Medium
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D${C_6}{H_5}C{H_2}OH$
d (d)
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Assertion :Nitrobenzene is used as a solvent in Friedel-Craft's reaction.
Reason : Fusion of nitrobenzene with solid $KOH$ gives a low yield of a mixture of $o-$ and $p-$ nitrophenols
when $\underset{(i)}{\mathop{\gamma =C{{H}_{3}}CO_{2}^{-},}}\,\,\,\,\,\,\underset{(ii)}{\mathop{Cl-C{{H}_{2}}-CO_{2}^{-},}}\,\,\,\,\,\,\,\underset{(iii)}{\mathop{Ph-SO_{3}^{-}}}\,$
In the given reaction $\begin{array}{*{20}{c}}
{{C_6}{H_5} - C - C{H_3}} \\
{||} \\
O
\end{array}$ $\xrightarrow{{N{H_2}OH/{H^ \oplus }}}X\xrightarrow{{Na/{C_2}{H_5}OH}}Y$. $Y$will be