- ✓$CsBr_3 \rightleftharpoons Cs^+ + Br^-$
- B$I_4O_9 \rightleftharpoons I^{3+} + (IO_3^-)_3$
- C$AgBrO_3 \rightleftharpoons Ag^+ + BrO_3^-$
- D$I_2O_4 \rightleftharpoons IO_2^- + IO_2^+$
$(C)$ $\theta_3 > \theta_2 > \theta_1$
$(D)$ Total $20$ unshared lone pairs are present
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| column $(I)$ | column $(II)$ | ||
| $(A)$ | Kohlraush law | $(i)$ | $\Lambda _{eq}^o = \Lambda _c^o + \Lambda _a^o$ |
| $(B)$ | Molar Conductivity |
$(ii)$ | $\Lambda _m = \frac{{K \times 1000}}{M}$ |
| $(C)$ | Degree of Dissociation |
$(iii)$ | $\alpha = {\Lambda _m}/\Lambda _m^o$ |
| $(D)$ | Dissociation Constant |
$(iv)$ | ${k_a} = C{\alpha ^2}/1 - \alpha $ |
[At. no. of $Mn = 25 ]$
The molar mass difference between compounds $Q$ and $R$ is $474 \mathrm{~mol}^{-1}$ and between compounds $P$ and $S$ is $172.5 \mathrm{~g} \mathrm{~mol}^{-1}$.
($1$)The number of heteroatoms present in one molecule of $R$ is. . . . . .
[Use: Molar mass (in g mol ${ }^{-1}$ ): $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$
Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms]
($2$)The total number of carbon atoms and heteroatoms present in one molecule of $S$. . . . . .
[Use: Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ ]: $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$
Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms
Give the answer quetion ($1$) and ($2$)