MCQ
Which is the correct sequence in the following, poperties? For the correct order mark $(T)$ and for the incorrect order mark $(F)$

$(a)$ Lewis acidity order : $SiF_4 < SiC_{4} < SiBr_4 < Sil_4$

$(b)$ Melting point : $NH_3 > SbH_3 > AsH_3 > PH_3$

$(c)$ Boiling point : $NH_3 > SbH_3 > AsH_3 > PH_3$

$(d)$ Dipole moment order : $NH_3 > SbH_3 > AsH_3 > PH_3$

  • $FTFT$
  • B
    $TFTF$
  • C
    $FFTT$
  • D
    $FFTF$

Answer

Correct option: A.
$FTFT$
a
$(a)$  $(F)$; As the sixe of halogen atom increases crowding on $Si$ atom will increase, hence, tendency of attack of Lewise base decreases

$(b)$  $(T)$ ; $M . P .$ of $N H_{3}$ is highest due to intermolecular $H$ -bonding in it .

Next lower $M.P.$ will be of $\mathrm{SbH}_{3}$ followed by $AsH_3$ due to high mol. wt. of $SbH_3$.

$(c)$  $(F)$ ; $M.P.$ and $B.P.$ of increase from $\mathrm{PH}_{3}$ to $\mathrm{SbH}_{3}$ via $\mathrm{AsH}_{3}$ due to increase in moL wt. $\mathrm{NH}_{3}$ does no follow this trend due to inter molecular $H-$ bonding.

Increasing $B.P.$ order $: \mathrm{PH}_{3}<\mathrm{AsH}_{3}<\mathrm{NH}_{3}<\mathrm{SbH}_{3}$

$(d)$ $(T)$ ; Value of bond moment decreases.

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