- AEthylene
- BBenzene
- ✓Hexane
- DAniline
Also, hexane is non-polar and concentrated $H _2 SO _4$ is polar, thus hexane is not soluble in $H _2 SO _4$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}} \\
|
\end{array}} \\
{C{H_3} - C - C{H_3}} \\
| \\
H
\end{array}{\mkern 1mu} $ $\mathop {\xrightarrow{{C{H_3}OBr}}}\limits_{C{H_3}OH} $
Minimum temperature at which it will become spontaneous is ..... $K.$(Integer)
$2SO_{2(g)} + O_{2(g)} \rightleftharpoons 2SO_{3(g)}$
has a value of $278$ at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature?
$SO_{3(g)} \rightleftharpoons SO_{2(g)} + \frac{1}{2} O_{2(g)}$
| Item $-I$ (Mixture) | Item $-II$ (Separation method) |
| $(a)$ $H_2O :$ Sugar | $p.$ Sublimation |
| $(b)$ $H_2O :$ Aniline | $q.$ Recrystallization |
| $(c)$ $H_2O :$ Toluene | $r.$ Stem distillation |
| $s.$ Differential extraction |