MCQ
Which of the following compounds is not colored yellow ?
- A$(NH_4)_3 [As (Mo_3O_{10})_4]$
- B$BaCrO_4$
- ✓$Zn_2[Fe(CN)_6]$
- D$K_3[Co(NO_2)_6]$
✓
Answer
Correct option: C.
$Zn_2[Fe(CN)_6]$
c
$Z n_{2}\left[F e(C N)_{6}\right], K_{3}\left[C o\left(N O_{2}\right)_{6}\right] $ and $\left(N H_{4}\right)_{3} A s\left[M o_{3} O_{l 0}\right]_{4}$ show color due to d-d transition while $B a C r O_{4}$ is coloured due to charge transfer phenomenon.
$Z n_{2}\left[F e(C N)_{6}\right], K_{3}\left[C o\left(N O_{2}\right)_{6}\right] $ and $\left(N H_{4}\right)_{3} A s\left[M o_{3} O_{l 0}\right]_{4}$ show color due to d-d transition while $B a C r O_{4}$ is coloured due to charge transfer phenomenon.
Further according to spectrochemical series the strong ligand possessing complex has higher energy and hence lower wavelength. Therefore, complexes containing $N O_{2}, N H_{4}^{+}, O^{2-}$ etc., ligands show yellow colour while $\mathrm{CN}^{-}$ forces the complex to impart white colour.
Spectrochemical series $I^{-} < B r^{-} < S^{2-} < S C N^{-} < C I^{-} < N O_{3}^{-} < N_{3}^{-} < F^{-} < O H^{-}$
$ < C_{2} O_{4}^{2-}=H_{2} O < N C S^{-} < C H_{3} C N < p y < N H_{3} < e n$
$ < b i p y < phen < N o_{2}^{-} < p p h_{3} < C N^{-}=C O$
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