MCQ
Which of the following compounds is optically active
- A${(C{H_3})_2}CHC{H_2}OH$
- B$C{H_3}C{H_2}OH$
- C$CC{l_2}{F_2}$
- ✓$C{H_3}CHOH{C_2}{H_5}$
✓
Answer
Correct option: D.
$C{H_3}CHOH{C_2}{H_5}$
d
(d)$\mathop {\mathop {\mathop {\mathop {C{H_3} - C - H}\limits^{\,\,\,\,\,\,\,\,|*} }\limits^{\,\,\,\,\,\,\,\,\,\,\,\,OH} }\limits_{\,\,\,\,\,|} }\limits_{\,\,\,\,\,\,\,\,\,\,\,\,\,{C_2}{H_5}} $
(d)$\mathop {\mathop {\mathop {\mathop {C{H_3} - C - H}\limits^{\,\,\,\,\,\,\,\,|*} }\limits^{\,\,\,\,\,\,\,\,\,\,\,\,OH} }\limits_{\,\,\,\,\,|} }\limits_{\,\,\,\,\,\,\,\,\,\,\,\,\,{C_2}{H_5}} $
In this structure chiral carbon is present that is why it is optically active.
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