MCQ
Which of the following is Loschmidt number
- A$6 \times {10^{23}}$
- ✓$2.69 \times {10^{19}}$
- C$3 \times {10^{23}}$
- DNone of these
✓
Answer
Correct option: B.
$2.69 \times {10^{19}}$
b
(b) The no. of molecules present in $1\,ml$ of gas at $STP$ is known as Laschmidt number.
(b) The no. of molecules present in $1\,ml$ of gas at $STP$ is known as Laschmidt number.
$22400\,ml$ of gas has total no. of molecules $ = 6.023 \times {10^{23}}$
$1\,ml$ of gas has total no. of molecules $ = \frac{{6.023 \times {{10}^{23}}}}{{22400}}$ $= 2.69 \times {10^{19}}$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A solution containing $62\,g$ ethylene glycol in $250\,g$ water is cooled to $-10\,^oC. $ If $K_f$ for water is $1.86\,K\,kg\,mol^{-1},$ the amount of water(in $g$ ) separated as ice is
→At $298\, K$ , the solubility product of $PbC{l_2}$ is $1.0 \times {10^{ - 6}}$. What will be the solubility of $PbC{l_2}$ in moles/litre
→The reaction $2{H_2}{O_2} \to 2{H_2}O + {O_2}$ is a
→For a reaction $A \rightarrow 2 B + C$ the half lives are $100\,s$ and $50\,s$ when the concentration of reactant $A$ is $0.5$ and $1.0 \,mol\,L ^{-1}$ respectively. The order of the reaction is (Nearest Integer)
→In the molecule $CH \equiv C - CH = C{H_2}$, the hybridisation of $C - C$ bond is
→The dissociation constant of $HCN$ is $5 \times {10^{ - 10}}$. The $pH$ of the solution prepared by mixing $1.5 $ mole of $HCN $ and $0.15$ moles of $KCN $ in water and making up the total volume to $0.5\,d{m^3}$ is
→Compound $P$ is neutral. $Q$ gives effervescence with $NaHCO _3$ while $R$ reacts with Hinsbergs reagent to give solid soluble in $NaOH$. Compound $P$ is
→Consider the reaction sequence below
→$[Figure]$ $\xrightarrow[{{\text{AlC}}{{\text{l}}_3}}]{{{\text{Succinic anhydride}}}}A\xrightarrow[{{\text{reduction}}}]{{{\text{Clemmenson 's}}}}X$ is
Maximum oxidation state central atom is present in
Which statement is not correct for nitrogen