- A

- ✓

- C

- D







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$6CO_2 + 6H_2O + solar energy \to C_6H_{12}O_6+6O_2$
A blue whales gain $75\ kg$ of mass per day by feeding on krill. The whale must consume ten times this mass of krill each day. The krill must consume $10.0\ kg$ of diatoms to produce $1.0\ kg$ of krill. Assuming that the mass gain of a whale's life is due to the consumption of carbohydrates $(C_6H_{12}O_6)$ , calculate the moles of $CO_2$ that must be used by the diatoms to produce the carbohydrates consumed by a blue whale in a day
Product of the above reaction will be
$CaC{O_3}\left( s \right)\overset \Delta \longleftrightarrow CaO\left( s \right) + C{O_2} \uparrow ,{K_p} = 8 \times {10^{ - 2}}$
$C{O_2}\left( g \right) + C\left( s \right) \rightleftharpoons 2CO\left( g \right),{K_p} = 2$