- A$PbO_2$
- ✓conc. $H_2SO_4$
- C$MnO_2$
- D$K_2Cr_2O_7/H^-$
$(a)$ $2{\text{HCl}} + {\text{Pb}}{{\text{O}}_2} \to {\text{PbO}} + {\text{C}}{{\text{l}}_2} \uparrow + {{\text{H}}_2}{\text{O}}$
$(b)$ $HCl + conc.{H_2}S{O_4} \to No\,reaction$
$(c)$ $4{\text{HCl}} + {\text{Mn}}{{\text{O}}_2} \to {\text{MnC}}{{\text{l}}_2} + 2C{l_2} \uparrow + 2{{\text{H}}_2}{\text{O}}$
$(d)$ $2{\text{HCl + }}{{\text{K}}_2}{\text{C}}{{\text{r}}_2}{{\text{O}}_7} + 12{{\text{H}}^ + } \to 2{\text{C}}{{\text{r}}^{3 + }}(aq.) + 2{{\text{K}}^ + }(aq.) + {\text{C}}{{\text{l}}_2} \uparrow + 7{{\text{H}}_2}{\text{O}}$
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$1$. $NH_3 + NH_4Cl$
$2$. $HCl + NaCl$
$3$. $NH_3 + HCl$ in $2 : 1$ $mole$ ratio
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