MCQ
Which of the following relations is correct for $k_f$ and $k_b$ in an equilibrium process that contains equal moles of reactants and products?
- A$k_f = k_b$
- B$k_f > k_b$
- ✓$k_f < k_b$
- DWe cannot predict
✓
Answer
Correct option: C.
$k_f < k_b$
c
$\mathrm{K}_{\mathrm{eq}}=\frac{\mathrm{k}_{\mathrm{f}}}{\mathrm{k}_{\mathrm{b}}}=\frac{\text { Conc. of proudcts as per rate law }}{\text { Conc. of reactants as per rate law }},$ stoichiometry of reaction is required.
$\mathrm{K}_{\mathrm{eq}}=\frac{\mathrm{k}_{\mathrm{f}}}{\mathrm{k}_{\mathrm{b}}}=\frac{\text { Conc. of proudcts as per rate law }}{\text { Conc. of reactants as per rate law }},$ stoichiometry of reaction is required.
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