MCQ
Which of the following sequence of reactions (reagents) can be used for the conversion of $C_6H_5CH_2CH_3$ into $C_6H_5CH = CH_2$ ?
- A$SOCl_2 :H_2O$
- ✓$SO_2Cl_2 :$ alc $KOH$
- C$Cl_2$ $/$ $hv$ $:$ $H_2O$
- D$SOCl_2$ $:$ alc $KOH$
✓
Answer
Correct option: B.
$SO_2Cl_2 :$ alc $KOH$
b
$SO_2Cl_2$ causes free radical substitution at benzylic position.
$SO_2Cl_2$ causes free radical substitution at benzylic position.
${C_6}{H_5}C{H_2}C{H_3}\xrightarrow{{S{O_2}C{l_2}}}{C_6}{H_5}CHClC{H_3}$ $\xrightarrow[{KOH}]{{alc}}{C_6}{H_5}CH = C{H_2}$
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