MCQ
Which one of the following metals will not reduce ${H_2}O$
- A$Ca$
- B$Fe$
- ✓$Cu$
- D$Li$
$E_{L{i^ + }/Li}^0 = - \,\,3.04\,\,V$ $E_{{H^ + }/{H_2}}^0 = 0.00\,V$
$E_{C{a^ + }/Ca}^0 = - 2.87\,V$ $E_{C{u^ + }/Cu}^0 = + 0.34\,V$
$Cu$ comes below $H$ in the electrochemical series.
Hence, unable to displace hydrogen from water.
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$[A]$ $HClO_4$ is more acidic than $\mathrm{HClO}$ because of the resonance stabilization of its anion
$[B]$ $HClO_4$ is formed in the reaction between $Cl_2$ and $H_2 O$
$[C]$ The central atom in both $HClO_4$ and $HClO$ is $s p^3$ hybridized
$[D]$ The conjugate base of $HClO_4$ is weaker base than $H_2 O$