Gujarat BoardEnglish MediumSTD 11 ScienceChemistryEquilibrium3 Marks
Question
Why do we pass $\mathrm{H}_2 \mathrm{S}$ gas in acidic medium in group 2?
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Answer
It is done so as to reduce concentration of $\left[\mathrm{SP}^{2-}\right]$ by common ion effect so that only group 2 radicals get precipitated whereas higher group radicals do not as $\mathrm{K}_{\text {sp }}$ of group II sulphides is low as compared to $\mathrm{K}_{\text {sp }}$ of sulphides of higher groups.
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