Question
Why does hard water not form lather with soap?

Answer

Soap is sodium or potassium salt of fatty acid. it is made up when alkali reacts with fatty acids. hardness of water is due to calcium and magnesium ions. sodium salts dissolve in water and hence lather is formed when soap is added to hard water, calcium and magnesium ions replaces sodium (or potassium) ions in the salt (soap) and gets precipitated hence lather formation is hindered.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

  1. List two main differences between orbit and orbital.
  2. If an electron is moving with a velocity 600m/ s which is accurate upto 0.005%, then calculate the uncertainty in its position.
($h = 6.626 \times 10^{-34}Js$ and mass of election = $9.11 \times 10^{-31}kg$)
Dual behaviour of matter proposed by de Broglie led to the discovery of electron microscope often used for the highly magnified images of biological molecules and other type of material. If the velocity of the electron in this microscope is $1.6 \times 10^6 \mathrm{~ms}^{-1}$, calculate de Broglie wavelength associated with this electron.
What is the energy in joules, required to shift the electron of the hydrogen atom from the first Bohr orbit to the fifth Bohr orbit and what is the wavelength of the light emitted when the electron returns to the ground state? The ground state electron energy is $=–2.18\times10^{-11}\text{ ergs}$.
Arrange the following:
  1. $\text{C}_6\text{H}_5\stackrel{+\ \ \ \ \ \ \ \ \ \ \ \ }{\text{CHCH}}_3, \text{C}_6\text{H}_5\stackrel{+\ \ \ \ \ \ \ \ \ \ \ \ }{\text{CHCH}}=\text{CH}_2,$ $\text{C}_6\text{H}_5\text{CH}_2\stackrel{+ \ \ \ }{\text{CH}}_2,\text{C}_6\text{H}_5\stackrel{+\ \ \ \ \ \ \ \ \ }{\text{C(CH}}_3)_2$ in order of increasing stability.
  2. $\text{CH}_3\text{CH}_2^+,\text{C}_6\text{H}_5\text{CH}_2^+,(\text{CH}_3)_3\text{C}^+,\text{CH}_2=\text{CHCH}_2^+$ in order of decreasing stability.
  3. $\text{HC}\equiv\text{C}^-,\text{CH}_2=\text{CH}^-,\text{CH}_3\text{CH}_2^-,\text{CH}^-_3,$ $(\text{CH}_3)_2\text{CH}^-,\text{C}_6\text{H}_5\text{CH}^-_2$ in order of increasing stability.
If $6.022 \times 10^{23}$ molecules of $\mathrm{N}_2$, react completely with $\mathrm{H}_2$ according to the equation:
$\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_3(\mathrm{~g})$
then calculate the number of molecules of $\mathrm{NH}_3$ formed.
Explain the structure of the $CO _2$ molecule.
Chlorophyll present in green leaves of plants absorbs light at $4.620 \times 10^{14}Hz$. Calculate the wavelength of radiation in nanometer. Which part of the electromagnetic spectrum does it belong to?
Find the temperature at which liquid water and water vapour will be in equilibrium.
$
\left(\Delta H_{\text {vap }}=40.73 kJ mol^{-1}=40.73 \times 1000 J mol^{-1}\right)
$
Note: Consider structures I to VII and answer the questions:
  1. $\text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{OH}$
  2. $\text{CH}_3-\text{CH}_2-\text{CH}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$
  3. $\ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{C}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \text{OH}$
  4. $\text{CH}_3-\text{CH}-\text{CH}_2-\text{OH}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
  5. $\text{CH}_3-\text{CH}_2-\text{O}-\text{CH}_2-\text{CH}_3$
  6. $\text{CH}_3-\text{O}-\text{CH}_2-\text{CH}_2-\text{CH}_3$
  7. $\text{CH}_3-\text{O}-\text{CH}-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
Identify the pairs of compounds that represents chain isomerism.
Emission transitions in the Paschen series end at orbit $n =3$ and start from orbit n and can be represeted as $v =$ $3.29 \times 10^{15}(Hz)\left[1 / 3^2-1 / n ^2\right]$ Calculate the value of n if the transition is observed at 1285 nm . Find the region of the spectrum.