Question
Why don't we have interference when two candles are placed close to each other and the intensity is seen at a distant screen? What happens if the candles are replaced by laser sources?
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$\text{P}+\text{pgh}+\frac{1}{2}\text{pv}^2$ = constant
or $\frac{\text{P}}{\text{pg}}+\text{h}+\frac{1}{2}\frac{\text{v}^2}{\text{g}}$ = another constant Here, $\frac{\text{P}}{\text{pg}}$ = pressure head; h = potential head and $\frac{1}{2}\frac{\text{v}^2}{\text{g}}$ velocity head. If the liquid is flowing through a horizontal tube, then h is constant, then according to Bernoulli’s theorem,$\frac{\text{P}}{\text{pg}}+\frac{1}{2}\frac{\text{v}^2}{\text{g}}$ constant
Bernoulli’s theorem is based on law of conser - vation of energy.2.T. Then, the velocity acquired by the body is

$\text{P}=\frac{1}{3}\text{ nmv}^2$
Where, n is number of molecules per unit volume, m is mass and v2 is mean squared speed. Though we choose the container to be a cube, the shape of the vessel really is immaterial. The average kinetic energy of a molecule is proportional to the absolute temperature of the gas; it is independent of pressure, volume or the nature of the ideal gas. This is a fundamental result relating temperature, a macroscopic measurable parameter of a gas (a thermodynamic variable as it is called) to a molecular quantity, namely the average kinetic energy of a molecule. The two domains are connected by the Boltzmann constant and given by E = kbT. Where kb is Boltzmann constant having value of 1.38 × 10-23 joule per Kelvin. We have seen that in thermal equilibrium at absolute temperature T, for each translational mode of motion, the average energy is $\frac{1}{2}\text{K}_\text{b}\text{t}$. The most elegant principle of classical statistical mechanics (first proved by Maxwell) states that this is so for each mode of energy: translational, rotational and vibrational. That is, in equilibrium, the total energy is equally distributed in all possible energy modes, with each mode having an average energy equal to $\frac{1}{2}\text{K}_\text{b}\text{t}$. This is known as the law of equipartition of energy. Accordingly, each translational and rotational degree of freedom of a molecule contributes $\frac{1}{2}\text{K}_\text{b}\text{t}$ to the energy, while each vibrational frequency contributes $2\times\frac{1}{2}\text{Kb T}=\text{K}_\text{b}\text{T}$ since a vibrational mode has both kinetic and potential energy modes.