Question
Why is it found experimentally difficult to detect neutrinos in nuclear $\beta$-decay?
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Answer
Neutrinos are neutral (chargeless), (almost) massless particles that hardly interact with matter.
Alternate Answer
The neutrinos can penetrate large quantity of matter without any interactionAlternate Answer
Neutrinos are chargeless and (almost) massless particles.Need a full question paper?
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If double slit apparatus is immersed in a liquid of refractive index, $\mu$ the wavelength of light reduces to $\lambda$ and fringe width also reduces to $\beta=\frac{\beta}{\mu}$.
The given figure shows a double-slit experiment in which coherent monochromatic light of wavelength $\lambda$ from a distant source is incident upon the two slits, each of width $\text{w}(\text{w}>>\lambda)$ and the interference pattern is viewed on a distant screen. A thin piece of glass of thickness t and refractive index n is placed between one of the slit and the screen, perpendicular to the light path.
→The given figure shows a double-slit experiment in which coherent monochromatic light of wavelength $\lambda$ from a distant source is incident upon the two slits, each of width $\text{w}(\text{w}>>\lambda)$ and the interference pattern is viewed on a distant screen. A thin piece of glass of thickness t and refractive index n is placed between one of the slit and the screen, perpendicular to the light path.
- ln Young's double slit interference pattern, the fringe width.
- Can be changed only by changing the wavelength of incident light.
- Can be changed only by changing the separation between the two slits.
- Can be changed either bychangingthe wavelength or by changing the separation between two sources.
- Is a universal constant and hence cannot be changed.
- If the width w ofone of the slits is increased to 2w, the become the amplitude due to slit.
- $1.5\text{a}$
- $\frac{\text{a}}{2}$
- $2\text{a}$
- No change.
- ln YDSE, let A and B be two slits. Films of thicknesses tA and tB and refractive indices mA and mB are placed in front of A and B, respectively. If $\mu_\text{A}\text{t}_\text{A}=\mu_\text{B}\text{t}_\text{B}$ then the central maxima will:
- Not shift.
- Shift towards A.
- Shift towards B.
- Shift towards A if tB = tA and shift towards B if tB < tA
- ln Young's double slit experiment, a third slit is made in between the double slits. Then:
- Fringes of unequal width are formed.
- Contrast between bright and dark fringes is reduced.
- Intensity of fringes totally disappears.
- Only bright tight is observed on the screen.
- ln Young's double slit experiment, if one of the slits is covered with a microscope cover slip, then:
- Fringe pattern disappears.
- The screen just gets illuminated.
- In the fringe pattern, the brightness of the bright fringes will decreases and the dark fringes will become more dark.
- Bright fringes will be more bright and dark fringes will become more dark.
In the derivation of P1 - P2 = Pgz, it was assumed that the liquid is incompressible. Why will this equation not be strictly valid for a compressible liquid?
In motor vehicles, a convex mirror is attached near the driver's seat to give him the view of the traffic behind. What is the special function of this convex mirror which a plane mirror can not do?
Explain the forward bias characteristics of $p-n$ junction diode with necessary graph.
→A magnetic dipole of magnetic moment 1.44A-m2 is placed horizontally with the north pole pointing towards north. Find the position of the neutral point if the horizontal component of the earth's magnetic field is $18 \mu\text{T}.$
→If the earth's magnetic field has a magnitude 3.4 × 10-5 T at the magnetic equator of the earth what would be its value at the earth's geomagnetic poles?
Consider a gravity-free hall in which an experimenter of mass 50kg is resting on a 5kg pillow, 8ft above the floor of the hall. He pushes the pillow down so that it starts falling at a speed of 8ft/s. The pillow makes a perfectly elastic collision with the floor, rebounds and reaches the experimenter's head. Find the time elapsed in the process.
The phenomenon of bending ofli ght around the sharp corners and the spreading of light within the geometrical shadow of the opaque obstacles is called diffraction of light. The light thus deviates from its linear path. The deviation becomes much more pronounced, when the dimensions of the aperture or the obstacle are comparable to the wavelength of light.
→- Light seems to propagate in rectilinear path because.
- Its spread is very large.
- Its wavelength is very small.
- Reflected from the upper surface of atmosphere.
- It is not absorbed by atmosphere.
- ln diffraction from a single slit the angular width of the central maxima does not depends on:
- $\lambda$ of light used.
- Width of slit.
- Distance of slits from the screen.
- Ratio of $\lambda$ and slit width.
- For a diffraction from a single slit, the intensity of the central point is:
- Infinite.
- Finite and same magnitude as the surrounding maxima.
- Finite but much larger than the surrounding maxima.
- Finite and substantially smaller than the surrounding maxima.
- Resolving power of telescope increases when:
- Wavelength of light decreases.
- Wavelength of light increases.
- Focal length of eye-piece increases.
- Focal length of eye-piece decreases.
- ln a single diffraction pattern observed on a screen placed at D metre di stance from the slit of width d metre, the ratio of the width of the central maxima to the width of other secondary maxima is:
- 2 : 1
- 1 : 2
- 1 : 1
- 3 : 1
The magnetic field due to the earth has a horizontal component of $26\mu\text{T}$ at a place where the dip is 60°. Find the vertical component and the magnitude of the field.
→Two long bar magnets are placed with their axes coinciding in such a way that the north pole of the first magnet is 2·0cm from the south pole of the second. If both the magnets have a pole strength of 10A-m, find the force exerted by one magnet on the other.