Wires $A$ and $B$ are made from the same material. $A$ has twice the diameter and three times the length of $B.$ If the elastic limits are not reached, when each is stretched by the same tension, the ratio of energy stored in $A$ to that in $B$ is
A$2:3$
B$3:4$
C$3:2$
D$6:1$
Medium
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B$3:4$
b (b) $U = \frac{1}{2}Fl = \frac{{{F^2}L}}{{2AY}}$. $U \propto \frac{L}{{{r^2}}}$ $(F$ and $Y$ are constant$)$
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