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Electric Power and House hold Circuits — Physics STD 10 — Question

ICSE BoardEnglish MediumSTD 10PhysicsElectric Power and House hold Circuits3 Marks
Question
With reference to the diagram shown below calculate:

(i) The equivalent resistance between $P$ and $Q.$
(ii) The reading of ammeter.
(iii) The electrical power between $P$ and $Q.$
✓

Answer

(i) $\frac{1}{ R }=\frac{1}{4}+\frac{1}{6}=\frac{3+2}{12}=\frac{5}{12}$
So, equivalent resistances
$=\frac{12}{5}=2.4 \Omega$
(ii) Here, $R = 2.4 \Omega$
$E = 2 \times 2 = 4 V$
From $E = IR$
$I =\frac{ E }{ R }$ or $I =\frac{4}{2.4}=1.66 A$
(iii) Power between $P$ and $Q$
$= I^2R$
$= (1.66)^2 \times (2.4) = 6.66$ watts

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