Question
Without using tables evaluate:
$\frac{2 \tan 53^{\circ}}{\cot 37^{\circ}}-\frac{\cot 80^{\circ}}{\tan 10^{\circ}}$.

Answer

$\frac{2 \tan 53^{\circ}}{\cot 37^{\circ}}-\frac{\cot 80^{\circ}}{\tan 10^{\circ}}$
$ =\left(\frac{2 \tan 53^{\circ}}{\cot \left(90^{\circ}-53^{\circ}\right)}-\left(\frac{\cot 80^{\circ}}{\tan \left(90-80^{\circ}\right)}\right)\right. $
$ =\left(\frac{2 \tan 53^{\circ}}{\tan 53^{\circ}}\right)-\left(\frac{\cot 80^{\circ}}{\cot 80^{\circ}}\right)$
$= 2 - 1$
$= 1$

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