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11. thermodynamics — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics11. thermodynamics1 Mark
MCQ
Work done in the cyclic process shown in figure is ...........
  • A
    $4 P_0 V_0$
  • B
    $-4 P_0 V_0$
  • ✓
    $-\frac{22}{7} P_0 V_0$
  • D
    $-13 P_0 V_0$
✓

Answer

Correct option: C.
$-\frac{22}{7} P_0 V_0$
c
(c)

Cyclic process is anticlockwise then

Work done $=-$ (Area of $P-V$ graph $)$

$W=-\pi R_1 R_2$

$=-\pi\left(\frac{3 P_0-P_0}{2}\right) \times\left(\frac{3 V_0-V_0}{2}\right)$

$=\frac{-22}{7} P_0 V_0$

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