Work done per mol in an isothermal change is
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(c)For isothermal process $PV = RT \Rightarrow P = \frac{{RT}}{V}$
$\therefore $W$ = PdV = \int_{\,{V_1}}^{\,{V_2}} {\frac{{RT}}{V}dV = RT} {\log _e}\frac{{{V_2}}}{{{V_1}}}$
$\therefore $W$ = PdV = \int_{\,{V_1}}^{\,{V_2}} {\frac{{RT}}{V}dV = RT} {\log _e}\frac{{{V_2}}}{{{V_1}}}$
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