Question
Work out the division: $96abc\ (3a – 12) (5b – 30)$ $\div$ $144\ (a – 4) (b – 6)$

Answer

$96abc (3a – 12) (5b – 30)$ $\div$ $144 (a – 4) (b – 6)$
$ = \frac{{96abc(3a - 12)(5b - 30)}}{{144(a - b)(b - 6)}}$
$ = \frac{{96abc \times 3(a - 4) \times 5(b - 6)}}{{144(a - 4)(b - 6)}}$
$= 10abc$

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