Question
Work out the surface area of following shape (use $\pi$ $= 3.14$).
✓
Answer
To find the total surface area, we draw the figure as given below.
$\therefore$ Upper surface area
$= 18 \times 3 + 8 \times 18 + 5 \times 18$
$= 54 + 144 + 90$
$= 288\ cm ^2$
$\therefore$ Lower surface area $= 288\ cm ^2$
$\therefore$ Surface area of thosse faces which are flat from right
$= 18 \times 18 + 2 \times 18 + 3 \times 18$
$= 324 + 36 + 54$
$= 414\ cm ^2$
Also, surface area of that face which are flat from left
$= 414\ cm ^2$
Surface area of from face
$= 18 \times 5 + 2 \times 8 + 8 \times 18 + 3 \times 2 + 3 \times 18 + 3 \times 3$
$= 90 + 16 + 144 + 6 + 54 + 9$
$= 319\ cm ^2$
Surface area of the bace face $= 319\ cm ^2$
$\therefore$ Total surface area
$= 288 + 288 + 414 + 414 + 319 + 319$
$= 288 + 1754$
$= 2042\ cm ^2$
$\therefore$ Upper surface area
$= 18 \times 3 + 8 \times 18 + 5 \times 18$
$= 54 + 144 + 90$
$= 288\ cm ^2$
$\therefore$ Lower surface area $= 288\ cm ^2$
$\therefore$ Surface area of thosse faces which are flat from right
$= 18 \times 18 + 2 \times 18 + 3 \times 18$
$= 324 + 36 + 54$
$= 414\ cm ^2$
Also, surface area of that face which are flat from left
$= 414\ cm ^2$
Surface area of from face
$= 18 \times 5 + 2 \times 8 + 8 \times 18 + 3 \times 2 + 3 \times 18 + 3 \times 3$
$= 90 + 16 + 144 + 6 + 54 + 9$
$= 319\ cm ^2$
Surface area of the bace face $= 319\ cm ^2$
$\therefore$ Total surface area
$= 288 + 288 + 414 + 414 + 319 + 319$
$= 288 + 1754$
$= 2042\ cm ^2$
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