Question
Write the centripetal force formula for an electron moving in a stationary orbit in a hydrogen atom and derive the formula for the radius of the orbit.

Answer

Form Rutherford's nuclear model of the atom, it can be said that atom is an electrically neutral sphere consisting of a very small, massive and positively charged nucleus at the centre surrounded by the revolving electrons in their respective dynamically stable orbits.
The electrostatic force of attraction $F _{ e }$ between the revolving electrons and the nucleus provides the required a centripetal force $F _{ c }$ to keep them in their orbits.
Thus, for a dynamically stable orbit in a hydrogen atom,
$F _{ e }= F _{ c }$
$\begin{aligned}
\therefore \quad \frac{1}{4 \pi \varepsilon_0} \cdot \frac{e^2}{r^2} & =\frac{m v^2}{r} \\
\therefore \quad \frac{1}{4 \pi \varepsilon_0} \cdot \frac{e^2}{r} & =m v^2 \\
\therefore \quad r & =\frac{e^2}{4 \pi \varepsilon_0 m v^2} \\
& \text { OR } \\
\therefore \quad v^2 & =\frac{e^2}{4 \pi \varepsilon_0 m r} \\
\therefore & =\sqrt{\frac{e^2}{4 \pi \varepsilon_0 m r}}
\end{aligned}$

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