Question
Write the correct number in the given boxes from the following A. P.
– 3, – 8, – 13, – 18, . . .
$\text { Here } t _3=\square, t _2=\square, t _4=\square, t _1=\square $
$ t _2- t _1=\square, t _3- t _2=\square $
$ \therefore a =\square, d =\square$

Answer

$-3,-8,-13,-18, \ldots$
First term $a =-3$
Second term $t_1=-8$
Third term $t _2=-13$
Fourth term $t_3=-18$
We know that $d=t_{n+1}-t_n$
Thus, $t _2- t _1=-13-(-8)=-13+8=-5$
$t_3-t_2=-18-(-13)=-18+13=-5$
Thus, $d=-5$

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